x^2+1.1x-2=0

Solution for x^2+1.1x-2=0 equation:

x^2+1.1x-2=0

a = 1; b = 1.1; c = -2;
Δ = b2-4ac
Δ = 1.12-4·1·(-2)
Δ = 9.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.1)-\sqrt{9.21}}{2*1}=\frac{-1.1-\sqrt{9.21}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.1)+\sqrt{9.21}}{2*1}=\frac{-1.1+\sqrt{9.21}}{2}
$